0=x^2+8x-294

Solution for 0=x^2+8x-294 equation:

0=x^2+8x-294

We move all terms to the left:

0-(x^2+8x-294)=0

We add all the numbers together, and all the variables

-(x^2+8x-294)=0

We get rid of parentheses

-x^2-8x+294=0

We add all the numbers together, and all the variables

-1x^2-8x+294=0

a = -1; b = -8; c = +294;
Δ = b2-4ac
Δ = -82-4·(-1)·294
Δ = 1240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1240}=\sqrt{4*310}=\sqrt{4}*\sqrt{310}=2\sqrt{310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{310}}{2*-1}=\frac{8-2\sqrt{310}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{310}}{2*-1}=\frac{8+2\sqrt{310}}{-2}
$